(2x^2y^4*4x^2y^4*3x)/(3x^-3y^2)

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Solution for (2x^2y^4*4x^2y^4*3x)/(3x^-3y^2) equation: 


D( x )

x = 0

3*x^-3*y^2 = 0

x = 0

x = 0

3*x^-3*y^2 = 0

3*x^-3*y^2 = 0

3*x^-3*y^2 = 0 // : 3*y^2

x^-3 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(2*3*4*x*x^2*x^2*y^4*y^4)/(3*x^-3*y^2) = 0

8*x^8*y^6 = 0 // : 8*y^6

x^8 = 0

x = 0

x in { 0} 

x belongs to the empty set

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